(5)/(x^2-3x)-(7)/x=(8)/(x-3)

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Solution for (5)/(x^2-3x)-(7)/x=(8)/(x-3) equation: 


D( x )

x^2-(3*x) = 0

x = 0

x-3 = 0

x^2-(3*x) = 0

x^2-(3*x) = 0

x^2-3*x = 0

x^2-3*x = 0

DELTA = (-3)^2-(0*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+3)/(1*2) or x = (3-9^(1/2))/(1*2)

x = 3 or x = 0

x = 0

x = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:0) U (0:3) U (3:+oo)

5/(x^2-(3*x))-(7/x) = 8/(x-3) // - 8/(x-3)

5/(x^2-(3*x))-(8/(x-3))-(7/x) = 0

5/(x^2-3*x)-8*(x-3)^-1-7*x^-1 = 0

5/(x^2-3*x)-8/(x-3)-7/x = 0

x^2-3*x = 0

x^2-3*x = 0

x*(x-3) = 0

x-3 = 0 // + 3

x = 3

x*(x-3) = 0

5/(x*(x-3))-8/(x-3)-7/x = 0

5/(x*(x-3))+(-8*x)/(x*(x-3))+(-7*(x-3))/(x*(x-3)) = 0

5-7*(x-3)-8*x = 0

5-8*x-7*x+21 = 0

26-15*x = 0

(26-15*x)/(x*(x-3)) = 0

(26-15*x)/(x*(x-3)) = 0 // * x*(x-3)

26-15*x = 0

26-15*x = 0 // - 26

-15*x = -26 // : -15

x = -26/(-15)

x = 26/15

x = 26/15

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